From: Jasper St. Pierre <jstpierre@mecheye.net>
Date: Thu, 14 Feb 2013 21:48:28 +0000 (-0500)
Subject: popupMenu: Treat a menu will all invisible menu items as empty
X-Git-Tag: archive/raspbian/50.5-1+rpi1~1^2~1013^2^2~4873
X-Git-Url: https://dgit.raspbian.org/%22http://www.example.com/cgi/%22/%22http:/www.example.com/cgi/%22?a=commitdiff_plain;h=30179bb60d9788faa04a2fb9703f15429da9727d;p=gnome-shell.git

popupMenu: Treat a menu will all invisible menu items as empty

As an example, a menu that has only settings actions might
be "empty" if allowSettings is false.

https://bugzilla.gnome.org/show_bug.cgi?id=681540
---

diff --git a/js/ui/popupMenu.js b/js/ui/popupMenu.js
index 9807b6275..5123696f3 100644
--- a/js/ui/popupMenu.js
+++ b/js/ui/popupMenu.js
@@ -914,7 +914,11 @@ const PopupMenuBase = new Lang.Class({
     },
 
     isEmpty: function() {
-        return this.box.get_n_children() == 0;
+        let hasVisibleChildren = this.box.get_children().some(function(child) {
+            return child.visible;
+        });
+
+        return !hasVisibleChildren;
     },
 
     isChildMenu: function(menu) {